Question

If the perimeter of a rectangle is 82 m and its area is 400sq m, then find breadth of the rectangle.

Answer 1

Perimeter of rectangle=2(l+b)

82=2(l+b)

$\frac{82}{2} = l + b$

41=l+b

l=41-b

Area of rectangle=l×b

400=l×b

400=b(41-b)

400=41b-b²

B ×(41-B) = 400

-b²+41b-400=0

b²-25b-16b+400=0

b(b-25)-16(b-25)=0

(b-16)(b-25)

Breadth=16cm

Length=25cm