Question

If the perimeter of a rectangle obtained by increasing one side of a square by 2 cm and decreasing another side by 2 cm is 64, then the side of the original square is

Answer 1

Answer:

IT'S A VERY EASY QUESTION

ANSWER IS 16cm

PERIMETER IS 64

SO SIDE IS 64cm DIVIDED BY 4

SO ANSWER IS 16cm

Answer 2

Step-by-step explanation:

Let side of the square = a m

If one side of a square is increased by 2 m

and other side is reduced by 2 m , a rectangle 

is formed 

Dimensions of the rectangle 

length = ( a + 2 ) m

Breadth = ( a - 2 ) m

According to the problem given ,

Perimeter of the rectangle = 48 m

2( l + b ) = 48

2 [ a + 2 + a - 2 ] = 48

2 × 2a = 48

4a = 48

a = 48 / 4

a = 12

Therefore side of the original 

square = a = 12m