Question

If the perimeter of a rectangle vegetable field and 280m and its length exceeds the width by 20m then what is the dimensions of the length?

Answer 1

Answer:

80 m

Step-by-step explanation:

Define x:

Let the breadth be x m

The length is (x + 20) m

Solve x:

perimeter = 2(Length + Breadth)

280 = 2( x+ x + 20)

280 = 2(2x + 20)

280 = 4x + 40

4x = 240

x = 60 m

Find the length:

Length = x + 20

Length = 60 + 20 = 80 m

Answer: The length is 80 m

Answer 2

Answer:

Length = 80 m, breadth = 60 m.

Step-by-step explanation:

Let the Breadth be x. Then,

Length = x + 20 m

Perimeter of rectangle = 280 m

➡️ 2( l + b) = 280 m

➡️ 2( x + 20 + x) = 280 m

➡️ 2(2x+ 20) = 280 m

➡️ 4x + 40 = 280 m

➡️ 4x = 240 m

➡️ x = 60 m

Breadth of rectangle field is 60 m.

Length of rectangle field is x + 20

Length of rectangle field is 60 + 20

Length of rectangle field is 80 m.