Question

If the perimeter of a rectangular house is 76 feet the length is 22 feet. what is the width?

Answer 1

given that perimeter of rectangle is 76

length=22

we know that perimeter of a rectangle is 2(l+b)

let the width be "a"

2(22+a)=76

44+2a= 76

2a= 76-44

2a=32

a=32/2

a= 16

so the width of the rectangle is 16feets

Answer 2

let width be B feet

perimeter = 2(L+B)

76= 2(22+B)

76 - 44/2 = B

B = 1 6 Feet