Question

if the perimeter of a rhombus is 100 cm and one of the diagonal is 40 cm,then the area of the rhombus in sq cm​

Answer 1

Answer:

❤️❤️Perimeter = 100 cm

In Rhombus all sides are equal so for getting lenght of one side we need to divide perimeter by 4 sides.

= 100 / 4

= 25 cm is lenght of each side.

Area of Rhombus = lenght of each diagonal / 2.

Inside the rhombus there forms a triangle with hypotenuse 25cm.

And one of side as 20cm. Which is half lenght of one diagonal.

So by Pythagoras method half lenght of other diagonal is

15cm.

So other diagonal would be 2 × 15 = 30cm.

Area = 30 × 40 / 2 = 600 sq. cm.❤️❤️

Step-by-step explanation:

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Answer 2

Answer:

600cm²

Step-by-step explanation:

Given :-

›› Perimeter of the rhombus is 100cm.

›› one of the diagonal is 40cm.

____________________

If the perimeter is 100cm

than one side is 100/4 = 25cm

____________________

By Separating the upper triangle_

x² + 20² = 25²

x² + 400 = 625

x² = 225

x = 15

we got the half other diagonal so, (15)2 = 30.

other diagonal = 30.

________________________

Area of Rhombus

= ½ × d1 × d2

= ½ × 30 × 40

= 600cm²