Math, asked by jk339697, 1 day ago

If the perimeter of a rhombus is 24 sq cm and one of the diagonals is 8 cm, then the area of the rhombus is

Answers

Answered by yenikapatisuribabu

0

area of rhombus = (d1×d2)÷2

area of given rhombus= (8×8)÷2

= 64÷2

32 sq.cm

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