Question

If the perimeter of a rhombus is 40 cm and one of its diagonal is 16 cm then what is the area of the rhombus

Answer 1

ur ans = 96cm^2

gud morning^_^

here is Ur ans

perimeter of rhombus formule:-4*side

40=4*side

10 cm = side of rhombus

D1= 16cm

D2=2×sqrt [side ^2 -(D1/2)^2]

= 2×sqrt [10^2 -(16/2)^2]

=2×sqrt [100- 64]

=2×sqrt. [36]

=12

=area = 1/2 D1 × D2

=12 × 16/2

=6 ×16

=> {96 cm^2}