Question

if the perimeter of a rhombus is 48 CM length of its diagonals is 15 cm and 20 cm find the distance between the two sides​

Answer 1

Since all the sides of rhombus are equal it's perimeter = 4× side

4× side = 48

side = 48/4 = 12

Area of rhombus = 1/2 ×( product of diagonals)

= 1/2 × (15×20)

= 1/2× 300

= 150 cm^ 2

distance between it's two sides can be termed as it's height

also Area of rhombus = base × height

150 = 12 × height

height = 150 /12

height = 12.5 cm