Question

If the perimeter of a rhombus is 4a and the length of the diagonal are x and y ,then it's area is

Answer 1

Answer:

$\frac{xy}{2}$

Step-by-step explanation:

area of rhombus = $\frac{1}{2}$*d1*d2    (d1= diagonal 1, d2=diagonal 2)

area of rhombus = $\frac{1}{2}$*x*y

area of rhombus = $\frac{xy}{2}$