if the perimeter of a rhombus is 52 and one diagonal is 10, what is the area of the rhombus
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let ,
length of one diagonal d1 = 10
and length of the other diagonal = d
therefore area of a rhombus = perimeter
= 1/2 ×d1 × d2 = 52
=1/2×10×d2. =52
=5×d2. =52
=d2. =52/5
=d2. =1.4
therefore d2 =1.4
hope it is correct.
length of one diagonal d1 = 10
and length of the other diagonal = d
therefore area of a rhombus = perimeter
= 1/2 ×d1 × d2 = 52
=1/2×10×d2. =52
=5×d2. =52
=d2. =52/5
=d2. =1.4
therefore d2 =1.4
hope it is correct.
Pubali11:
the length of the other diagonal be d2 it is not d by mistake
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