If the perimeter of a rhombus is 80 cm and one of its diagonal is 24 cm, then what is the area (in cm2) of the rhombus?
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Step-by-step explanation:
perimeter =2√ p square + Q square
=2√(24)(24)+q*q=80
(24)(24)+Q*Q=160
q*q=160-576
q=√416
Area =1/2(24)(√416)
=12√416 cm square
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