Question

If the perimeter of a right angled triangle is 60 cm and its hypotenuse is 25 cm, find its area.


Solve it,,,​

Answer 1

Answer:

perimeter of square is 60 cm

according to square property, all sides of square are equal

therefore side of square=15 cm(60/4=15)

area of sqaure=(side)2

=(15)2

=225 sqcm

Step-by-step explanation:

hope it help you

Answer 2

$hello$

Perimeter of that triangle = 60cm

The measure of hypotaneous = 25cm

Then the rest sides must measure = 60-25

= 35

Let one side be x

Then, the measure of the third side must be

35 - x

Using pythagoras theorem

(25)^2 =(x)^2 + (35-x)^2

625 = x^2 + x^2 - 70x + 1225

x^2 + x^2 - 70x + 1225 = 625

x^2 + x^2 - 70x + 1225 -625 = 0

2 x^2 - 70x + 600 = 0

2x^2 - 40x - 30 x + 600= 0

2x (x-20) -30 ( x - 20) = 0

(x-20)(2x-30)=0

x -20 = 0

x = 20

2x -30 =0

2x =30

x = 15

So, one of the side measure either 20 cm 15 cm

If one side measure 20cm then the other must measure 35 -20 = 15cm

And if it measured 15 cm then the other side measure 35-15 = 20 cm

So, we will get 20cm and 15 cm as our remaining sides.

One of then will be height and the other misy be the base..

Now apply the formula of area of triangle i.e

(1/2) (height)(base)

= (1/2 )(20)(15)

= 150 cm^2

So, the area of that triangle will be 150 cm^2.

Answer: 150 cm^2

I hope my answer helps you.....✌

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