Question

If the perimeter of a right-sided right-angled triangle is (6 + 3/2) meters, what is the area of ​​that triangle?​

Answer 1

Answer:

HEY BUDDY HERE IS YOUR ANSWER:-

Step-by-step explanation:

In an isosceles right angled triangle, the two sides on the right angle are equal.

Let the equal sides be a.

Hence, hypotenuse of the isosceles right angled triangle =a2+a2=2a

Given, perimeter of the triangle =(6+32)m

⇒a+a+2a=(6+32)m

⇒a(2+2)=3(2+2)m

⇒a=3m

In the isosceles right triangle, the base and height =a

Hence, area of the triangle = 21×base×height =21×3×3= 4.5m2

Hence the answer is 4.5 m^2

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