Question

If the perimeter of a room is 18m and it lsa is 63m2, then the height of the room is

Answer 1

Step-by-step explanation:

perimeter = 2(l+b)

2(l+b)= 18 m

l+b= 9m

area = l×b

63=l×b

(l+b)²= l²+ b² + 2lb

81 = l²+b² + 186

L²+b² = 100

Answer 2

Answer:

2(L+B) = 18   and  2(L+B)*H  = 63

Thus 18H = 63

H  = 63/18  =  3.5 metre

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