if the perimeter of a semi circle protactor is 108 find the diameter of protactor
Answers
Answered by
1
Let radius=r
Perimeter of protractor=half of circumference+diameter
πr+2r
Given, perimeter =108
πr+2r=108
r(π+2)=108
r(22/7+2)=108
r(22+14/7)=108
r(36/7)=108
r=108*(7/36)
r=3*7
r=21
Therefore, diameter2r=2*21=42cm
Answered by
1
Answer:
5.55cm is the radius of the semicircle
Step-by-step explanation:
(π*r*r)+2*r=108
22r^2+14r-756=0
11r^2+7r-378=0
r=-7+-√47+16632/22
=-7+-129.14/22
radius cannot be -ve so
129.14-7/22 is the answer
ie.5.55cm
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