Question

If the perimeter of a semi circular park is 252 m, Find its Area​

Answer 1

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Perimeter= πr+2r= 252m

$\sf \: r( \frac{22}{7} + 2) = 252$

$\sf \: r \: \frac{22 + 14}{7} = 252$

$\sf \: r \times \frac{36}{7} = 252$

$\sf \: r = \frac{252 \times 7}{36} = 7$

So radius= 7m

$\sf \: Area = \frac{\pi {r}^{2} }{2}$

$\sf= \frac{22}{7} \times \frac{7 \times 7}{2} = {77m}^{2}$

So Area is 77m²

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Answer 2

Answer:

$\fbox a \: \fbox n \: \fbox s \: \fbox w \: \fbox e \: \fbox r$

Perimeter=πr+2r=252 m

$r( \frac{2}{7} + 2) = 252 \\ r( \frac{22 + 14}{7}) = 252 \\ r \times \frac{36}{7} = 252 \\ so \: radius = 7m \\ area = \frac{\pi {r}^{2} }{2} \\ = \frac{22}{7} \times \frac{7 \times 7}{2} = 77 {m}^{2} \\ so \: area \: is \: 77 {m}^{2}$

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