if the perimeter of a semicircular protractor is 108 CM then find the diameter of the protector
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2
Perimetwr of semicircle = πr
108 = 22/7*r
108*7/22 = r
r = 34 cm
Diameter = r*2 = 34*2 = 68 cm
108 = 22/7*r
108*7/22 = r
r = 34 cm
Diameter = r*2 = 34*2 = 68 cm
Answered by
0
Perimeter = π*r (circumference of circle = 2πr)
22\7×x=108
x\7 = 54/11
x=54*7/11
=34.363
diameter = 68.72
22\7×x=108
x\7 = 54/11
x=54*7/11
=34.363
diameter = 68.72
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