Question

if the perimeter of a semicircular protractor is 36 cm find its diameter ​

Answer 1

Perimeter of protractor = πr+2r units.
36 = r(π+2)
36 = r(22/7+2)
36 = r(22+14/7)
36 = r(36/7)
36 = 36r/7
r/7 = 36/36
r/7 = 1
r =7 cm
Diameter = 2r = 2(7) = 14
Thus the diameter of the protractor is 14 cm

Answer 2

$\pi \: r = 36$
$r = \frac{36}{\pi}$
$r = \frac{36 \times 7}{22}$
$r = 11.4cm$
$diameter = 2r$
$diameter = 22.8cm$
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