Math, asked by saurav6945, 1 year ago

if the perimeter of a semicircular protractor is 36 CM then find its diameter?

Answers

Answered by iambrainlyhelper
21
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perimeter of a semicircular protractor


= perimeter of a semicircle = (2r+πr)cm [given]

2r+πr=36


r \times  \frac{36}{7}  = 36 \\ r = 7 \\
diameter = 2r =2×7=14cm



so, the diameter of a semicircle protector is 14 cm .


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10304: why we are adding 2r
Answered by QHM
37
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