Question

if the perimeter of a semicircular protractor is 36 CM then find its diameter?

Answer 1

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perimeter of a semicircular protractor


= perimeter of a semicircle = (2r+πr)cm [given]

2r+πr=36


$r \times \frac{36}{7} = 36 \\ r = 7$
diameter = 2r =2×7=14cm



so, the diameter of a semicircle protector is 14 cm .


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Answer 2

The answer is provided in the attachment.
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