if the perimeter of a semicircular protractor is 36cm. find its diameter(π=22\7
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Answered by
0
Answer:
the perimeter of semicircular protractor is
1/2x2xpiexr +2r ..... so
1/2x2xpiexr+2r= 36 (given)
aage aap khud solve krlo......
Answered by
4
1/2 *2*22/7*r +2r=36
22/7*r+2r=36
r(22/7+2)=36
r(36/7)=36
r=36*7/36
r=7
D=14
22/7*r+2r=36
r(22/7+2)=36
r(36/7)=36
r=36*7/36
r=7
D=14
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