Math, asked by expertguru5854, 1 year ago

If the perimeter of a semicircular protractor is 66cm find the radius of protector

Answers

Answered by Anonymous
10

the perimeter is 66

 \frac{1}{2} 2 \times  \pi \times  r \\   \frac{22}{7}  \times r = 66 \\ r = 66 \times  \frac{7}{22}  \\ r = 21 \: cm \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: |hope \: it \: will \: help \: you|  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: |thank \: you|

Answered by wifilethbridge
7

The radius of protector is 12.84 cm

Step-by-step explanation:

Perimeter of  semi circular Protector = \pi r +2r

Where r is the radius

We are given that the perimeter of semi circular protractor is 66cm

So,\pi r+2r = 66

3.14r+2r=66\\r(3.14 +2)=66\\5.14r=66\\r=\frac{66}{5.14}\\r=12.84

Hence The radius of protector is 12.84 cm

#Learn more:

Find perimeter and area of semicircle. diameter of. semicircle = 12

https://brainly.in/question/1109340

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