Question

If the perimeter of a semicircular protractor is 72 cm where π = 22/7 then the diameter of protractor is​

Answer 1

Answer:

Perimeter of semicircular protractor = 72 cm

This gives

∏r + 2r = 72

r(∏ + 2) = 72

r(22 + 14)/7 = 72

r(36)/7 = 72

r = 72 x 7 / 36

r = 14 cm