Question

if the perimeter of a square and rectangle is equal which of the two has greater area​

Answer 1

Step-by-step explanation:

Assume a square of side s and rectangle with one side as a and b.

Since the perimeters are equal

4s = 2(a+b)

or b = 2s-a.

The sides of rectangle can be rewritten as a and 2s-a.

Areas are

s² and (2s-a)a

If they are equal

s² = 2sa - a²

s² -2sa + a² = 0

(s-a)² = 0

s=a

so only when s = a, both perimeter and area are equal. This is the trivial case where square is also taken as rrctanɡle also.

In all other cases, no area of rectanɡle amd square are not equal