If the perimeter of a square increases by
25%, what is the increase in its area?
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Answered by
3
Answer:
Area increases by 56.25%
Step-by-step explanation:
Perimeter of square = 4a
Let the new perimeter after an increment of 25% be 4a'. That is,
4a' = 4a+4a*0.25
4a' = 5a
a' = 5a/4
Initial area = a²
Area after the increament of 25% in perimeter = (a')² = (5a/4)² = 25a²/16
Percent increment in area = {(25a²/16 - a²)/a²}*100 = (9a²/16a²)*100 = 900/16 = 56.25%
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1
Answer:
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