Question

if the perimeter of a square is 200 cm find it's area?​

Answer 1

Step-by-step explanation:

Given,

Perimeter of square =200 cm

Then,

Area of square = ?

Perimeter of square =4×side

200=4×side

side=200/4

side=50 cm

Now,

Area of square = (Side×side)

50×50cm

2500 cm^2

I hope it will helps you ¯\(◉‿◉)/¯

Answer 2

$\begin{gathered}\begin{gathered}\bf \: Given - \begin{cases} &\tt{perimeter \: of \: square = 200 \: cm} \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \: To\: find - \begin{cases} &\sf{area \: of \: square}  \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\Large{\bold{\blue{\underline{Formula \: Used \::}}}} \end{gathered}$

$(1). \:\boxed{ \green{ \bf \:Perimeter_{(square)} = 4 \times side}}$

$(2).\:\boxed{ \green{ \bf \: Area_{(square)} = {(side)}^{2} }}$

$\large\underline\purple{\bold{Solution :- }}$

Given that

• Perimeter of square = 200 cm

$\tt \longmapsto\:4 \times side \: = 200 \:$

$\rm :\implies\:side \: = \: \cancel{\dfrac{200}{4}} = 50 \: cm$

Now,

• we know that

$\tt \longmapsto\:Area_{(square)} = {(side)}^{2}$

$\rm :\implies\:Area_{(square)} = {(50)}^{2}$

$\rm :\implies\:Area_{(square)} = 2500 \: {cm}^{2}$

More information :-

Perimeter of rectangle = 2(length× breadth)

Diagonal of rectangle = √(length ²+breadth ²)

Area of square = side²

Perimeter of square = 4× side

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²