if the perimeter of a Trapezium is 104 if non parallel sides are 18 M and 22 M and its altitude is 6 m find the area of trapezium
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Perimeter of trapezium = 104
=> Sum of paralell sides +sum of non Parallel sides = 104
=> Sum of paralell sides = 104 - (18+22)
= 104 - 40
=> 64 cm
Area = sum of paralell sides *h/2
= 64*6/2
= 64 * 3
= 192 cm^2
=> Sum of paralell sides +sum of non Parallel sides = 104
=> Sum of paralell sides = 104 - (18+22)
= 104 - 40
=> 64 cm
Area = sum of paralell sides *h/2
= 64*6/2
= 64 * 3
= 192 cm^2
SUPERSSS25:
Do you know trapeze area formula
6 is height
yes
Google area you will understand
how 6 is height
All the best!
please explain me please
are you Gaurav Bhaiya
Sorry but I have tried my best to explain but you are not understanding so I can't do anything more
ok only explain how you have formed 6 by 2
Answered by
0
192 cm^2
Reason,
Both Parallel sides measurement = 104-40=64.
a+b = 64
(18+22=40)
1/2*h*(a+b)
1/2*6*64 =3*64
=192
Reason,
Both Parallel sides measurement = 104-40=64.
a+b = 64
(18+22=40)
1/2*h*(a+b)
1/2*6*64 =3*64
=192
I hope would understand this!
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