If the perimeter of a trapezium is 68 cm its non- parallel sides are equal to 12 cm each and its altitude is 4 cm find the area of the trapezium. fast ,fast
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Answered by
32
area of a trapezium- 1/2*h*(a+b)
perimeter- a+b+c+d
here,sum of non //sides=24
hence the sum of // sides=44cm
hence are= 1/2*4*44=88cm^2
perimeter- a+b+c+d
here,sum of non //sides=24
hence the sum of // sides=44cm
hence are= 1/2*4*44=88cm^2
Answered by
69
We know that area of a trapezium = 1/2 x (sum of parallel sides) x altitude
So in order to find the sum of parallel sides we subtract the length of non - parallel sides from the perimeter.
Thus, we have 68 - (12 x 2) [As two sides are equal to 12cm)
= 68 - 24
= 44cm
Therefore area = 1/2 x 44 x 4
= 22 x 4
= 88 cm²
Hope that helps !!
So in order to find the sum of parallel sides we subtract the length of non - parallel sides from the perimeter.
Thus, we have 68 - (12 x 2) [As two sides are equal to 12cm)
= 68 - 24
= 44cm
Therefore area = 1/2 x 44 x 4
= 22 x 4
= 88 cm²
Hope that helps !!
yes :)
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So in order to find the sum of parallel sides we subtract the length of non - parallel sides from the perimeter.
Thus, we have 68 - (12 x 2) [As two sides are equal to 12cm)
= 68 - 24
= 44cm
Therefore area = 1/2 x 44 x 4
= 22 x 4
= 88 cm²