If the perimeter of a trapezium is 70 em and the length of non parallel sides are equal to 23 cm then the sum of parallel sides is (a) 23 (b) 24 (C) 25 (d) 26
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Step-by-step explanation:
Draw a line BC parallel to AD
Draw a perpendicular line BE on DF
ABCD is a parallelogram.
BC=AD=25 cm
CD=AB=60 cm
CF=77−CD=17cm
For ΔBCF
semiperimeter of triangle=
2
25+26+17
=
2
68
=34
By Heron's Formula of triangle=
s(s−a)(s−b)(s−c)
=
34(34−25)(34−26)(34−17
)
=204cm²
Also, area of ΔBCF=
2
1
×base×height
204=
2
1
BE×CF
204=
2
1
BE×17
BE=408/17
BE=24 cm
Area of Trapezium=
2
1
(AB+DF)×BE
=1/2(60+77)×24
Area=1644cm²
solution
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