Question

If the perimeter of a triangle is 32 cm and the sides are 8 cm and 11 cm , find its area.



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Answer 1

$A = 43.82 \: {cm}^{2}$

$a \:( Side) = 8 \: cm$

$b(Base) = 11 \: cm$

$p \: (perimeter) = 32 \: cm$

Using the formulas

$A = \sqrt{s(s - a)(s - b)(s - c)}$

$P = a + b + c$

$s = \frac{a + b + c}{2}$

Solving for A

$A = \frac{1}{4} \sqrt{ - P {}^{4} + 4 \: P {}^{3} b - 4(Pa) {}^{2} - 12 \:P {}^{2} a \: b - 4(p \: b) {}^{2} + 8 \: P \: a \: b {}^{2} }$

$≈43.8178cm²$

Answer 2

Answer:

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