If the perimeter of a triangle is 32 cm and the sides are 8 cm and 11 cm, find its area
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Given :-
If the perimeter of a triangle is 32 cm and the sides are 8 cm and 11 cm
To Find :-
Area
Solution :-
Let the third side be c
- Perimeter = a + b + c
- 32 = 8 + 11 + c
- 32 = 19 + c
- 32 - 19 = c
- 13 = c
Now,
- Semperimeter = a + b + c/2
- Semiperimeter = 8 + 11 + 13/2
- Semiperimeter = 32/2
- Semiperimeter = 16 cm
Now,
- Area = √s(s - a)(s - b)(s - c)
- Area = √16(16 - 8)(16 - 11)(16 - 13)
- Area = √16(8)(5)(3)
- Area = √1920
- Area = 43.81 cm²
∴ Area is 43.81 cm²
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