Question

If the perimeter of a triangle is 32 cm and the sides are 8 cm and 11 cm, find it's area.​

Answer 1

If the perimeter of a triangle is 32 cm and the sides are 8 cm and 11 cm, find it's area.

Answer:

.Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=11 cm and 2s=32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11=5,s−c=16−13=3

Hence, area of given triangle =

s(s−a)(s−b)(s−c)

=

16×8×5×3

=8

30

cm

2

Answer 2

Answer:

• 44 cm

Step-by-step explanation:

Area of triangle = 1/2 * b * h

= 1/2 * 8 * 11

= 4 * 11

= 44 cm