If the perimeter of a triangle is (4y-3x+2z) CM and two sides of the triangle measure (4x+2y+z) CM and (3x+7y-2z)cm ,find the length of the third side of the triangle.
Answers
Answered by
5
use formula
a+b+c=perimeter
perimeter-(a+b)=c
a+b+c=perimeter
perimeter-(a+b)=c
RiyaMondal:
it's worry
Answered by
7
Given,
AB+BC+CA=(4y-3x+2z)cm
let,
AB=(4x+2y+z)cm
let,
BC=(3x+7y+2z)cm
perimeter of triangle= AB+BC+CA ------eq_1
put value of BC and CA in eq 1
CA+4x+2y+z+3x +7y+2z = 4y-3x+2z
CA+7x+9y+3z = 4y-3x+2z
CA = 4y-3x+2z-7x-9y-3z
CA = -5y-10x-z
:
:
:
its my answer thank's
AB+BC+CA=(4y-3x+2z)cm
let,
AB=(4x+2y+z)cm
let,
BC=(3x+7y+2z)cm
perimeter of triangle= AB+BC+CA ------eq_1
put value of BC and CA in eq 1
CA+4x+2y+z+3x +7y+2z = 4y-3x+2z
CA+7x+9y+3z = 4y-3x+2z
CA = 4y-3x+2z-7x-9y-3z
CA = -5y-10x-z
:
:
:
its my answer thank's
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