Question

If the perimeter of a triangle is (4y-3x+2z) CM and two sides of the triangle measure (4x+2y+z) CM and (3x+7y-2z)cm ,find the length of the third side of the triangle.

Answer 1

use formula
a+b+c=perimeter
perimeter-(a+b)=c

Answer 2

Given,
AB+BC+CA=(4y-3x+2z)cm

let,
AB=(4x+2y+z)cm
let,
BC=(3x+7y+2z)cm

perimeter of triangle= AB+BC+CA ------eq_1
put value of BC and CA in eq 1 

CA+4x+2y+z+3x +7y+2z = 4y-3x+2z
CA+7x+9y+3z = 4y-3x+2z
CA = 4y-3x+2z-7x-9y-3z
CA = -5y-10x-z
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its my answer thank's