If the perimeter of a triangle is given by 3x - y + t and two of it sides are given by 4x - 9 and 12y - x + 8 then find its third side.
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Answer:
4x-9+12y-x+8 +( third side) = 3x-y+t
3x+12y-1 + ( third side) = 3x-y+t
if you compare ,
add ( -13y )on LHS ,to get -y.
and ( 1+t ) on LHS ,to get t.
so finally third side will be like ( -13y+t+1)
ok ya.
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