Math, asked by wahab4465, 1 year ago

If the perimeter of an isosceles right triangle is (6+3√2)m then the area of the triangle is

Answers

Answered by muskaan1858
13
Let, equal sides of the triangle=X
in triangle ABC
by Pythagorous theorem,
X•X+X•X=BC•BC
2 {x}^{2}  = bc
bc =  \sqrt{2}x
perimeter=6+3√2
2X+√2X=6+3√2
X(2+√2)=6+3√2
X=6+3√2/2+√2
X=3√2(√2+1)/√2(√2+1)
X=3m
BC=3√2
Answered by foreign39
0

Step-by-step explanation:

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