If the perimeter of an isosceles right triangle is ( 6+3√2 )m , then the area of the triangle is
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it should be divided in a proportion
if it's (2x+x√2)
then=x+x+x√2
so [2(3)+3√2]
then=3+3+3√2
the biggest side i.e 3√2 is hypotenuse
the other side should be multiplied by each other
3×3=9
then they should be divided by 2
9/2=4.5
the area is 4.5cm²
please mark me as brainliest
if it's (2x+x√2)
then=x+x+x√2
so [2(3)+3√2]
then=3+3+3√2
the biggest side i.e 3√2 is hypotenuse
the other side should be multiplied by each other
3×3=9
then they should be divided by 2
9/2=4.5
the area is 4.5cm²
please mark me as brainliest
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