Question

if the perimeter of rectangle be 160 unit and the length exceed the breadth by 7units find the area of rectangle
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Answer 1

Answer:

6387.75units

Step-by-step explanation:

let breadth be x

, then length= (x+7)

perimeter= x+(x+7)

160=x+x+7

160=2x+7

160-7=2x

x=153/2

=>76.5units

so breadth=76.5units and

length=76.5+7=83.5units

Area= lb

Area=76.5×83.5

area=6387.75units

Answer 2

Answer:

1567.75

Step-by-step explanation:

Length = x+7

Breadth=×

Perimeter = 2({x+7}+x)

=2(2x+7)

160=4x+14

160-14=4x

146=4x

x=146÷4

Breadth=36.5

Length =43.5

Area = 43.5 × 36.5

=1567.75