Question

If the perimeter of rectangle is 24 and it's length is 7 cm. Find its area

Answer 1

Answer:

$\huge \bf \: given$

• Perimeter of rectangle = 24 cm
• Length = 7 cm

$\huge \bf \: to \: find \:$

Area

$\huge \bf \: solution$

First we have to find its breadth

$perimeter \: = 2(l + b)$

$24 = 2(7 + b)$

$24 - 14 = 2b$

$10 = 2b$

$b \: = \frac{10}{2}$

$b \: = 5$

Now finding area

$area \: = l \: \times b$

$area \: = 5 \times 7$

$area \: = {35 \: cm}^{2}$

Answer 2

Answer:

First we have to find its breadth

perimeter \: = 2(l + b)perimeter=2(l+b)

24 = 2(7 + b)24=2(7+b)

24 - 14 = 2b24−14=2b

10 = 2b10=2b

b \: = \frac{10}{2}b=

2

10

b \: = 5b=5

Now finding area

area \: = l \: \times barea=l×b

area \: = 5 \times 7area=5×7

area \: = {35 \: cm}^{2}area=35cm

2