if the perimeter of rhombus is 100 cm and length of one diagonal is 48 cm, what is the area of the quadrilateral?
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Answer:
336 sq.cm
Step-by-step explanation:
Perimeter is 100cm...so,length of one side is 25cm
Then consider the two diagonals dividing the rhombus into 4 right angled triangles
Here,the hypotenuse=25cm
and one side=48/2=24cm
Using pythagoras theorem,the other side will be 7cm
Which means the other diagonal length=14cm
So,area of the rhombus
=(48*14)/2
=336 sq.cm.
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