Question

If the perimeter of the recatngle is 13 cm and its width is 2 3/4, then its length is

Answer 1

perimeter = 2(l +b)

13 = 2(l + 15/4)

13/2 = l + 15/4

l = 13/2 -15/4 = (13×2 - 15)/4= 11/4

Answer 2

Answer:

p=13,b=2x3/4=3/2

p=2(l+b)

13=2x(l+3/2)

13/2-3/2=l

10/2=l

l=5