Question

If the perimeter of the rectangle is 82 metres and the area is 400 m 2, the breadth of the rectangle is

Answer 1

put:
breadth = b
.......................
length    = a
.......................
2(a+b)   = 82→ a+b = 41→a = 41 - b
........................
a*b        = 400
.......................
(41-b)*b = 400
.......................
41b - b^2 = 400
.........................
b^2 -41b + 400 = 0
...........................
Δ = (-41)^2 - 4(1)(400) = 81 
..........................................
b = (41+- √81)/2 = (41 +- 9)/2 = 16 or 25
...............................................................
25 is length and 16 is breadth
...............................................................
plz mark me as brainliest
...............................................................

Answer 2

SOLUTION :  

Given :  

Perimeter of a rectangular field = 82 m

Area of a rectangular field = 400 m²

Let the breadth of a rectangle be 'b’ m.

Perimeter of a rectangle = 2(l + b)

82 = 2(l + b)

82/2 = (l + b)

l + b = 41  

Length,l = 41 - b …………(1)

Area of a rectangle  = l × b

400 = (41 - b) b

[From eq 1]

400 = 41b - b²

b² - 41b + 400 = 0

b² - 25b - 16b + 400 = 0

[By middle term splitting]

b(b - 25) - 16(b - 25) = 0

(b - 25) (b - 16) = 0

(b - 25) = 0  or  (b - 16) = 0

b = 25 or b = 16  

If breadth,b = 25 , then length, l = 41 - b  

l = 41 - 25 = 16 m

If breadth,b = 16 , then length, l = 41 - b  

l = 41 - 16 = 25 m

Since, length is more than breadth  

Therefore , breadth, b = 16 m

HOPE THIS ANSWER WILL HELP YOU...