Question

If the perimeter of the Rhombus is 100cm and one of it's diagonal is 40cm, then the area of the rhombus is

Answer 1

Answer:

Explanation:

Perimeter = 100 cm

In Rhombus all sides are equal so for getting length of one side we need to divide perimeter by 4 sides.

= 100 / 4

= 25 cm is lenght of each side.

Area of Rhombus = lenght of each diagonal / 2.

Inside the rhombus there forms a triangle with hypotenuse 25cm.

And one of side as 20cm. Which is half lenght of one diagonal.

So by Pythagoras method half lenght of other diagonal is

15cm.

So other diagonal would be 2 × 15 = 30cm.

Area = 30 × 40 / 2 = 600 sq. cm.

Answer 2

Answer:

Why does an object float or sink when placed on the surface of water? ... * An object sinks in water if its density is greater than that of water. * An object floats in water if its density is less than that of water.