If the perimeter of the rhombus is 20cm and one of the diagonal is 8cm. Then find the area of the rhombus
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Given
Perimeter of the rhombus = 20cm
Length of diagonal = 8cm
NOTE :-
•Diagonals of rhombus bisect each other at 90°
•Perimeter of rhombus = 4a
where a = side of rhombus
Area of rhombus
1/2 × product of diagonal
1/2 × 8 × 6
4×6
24 sq.cm
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Step-by-step explanation:
Perimeter of rhombus = 4a
then Side = 20cm
now, diagonals of rhombus bisects each other therefore , one half of other diag = √(20²-4²)
> √(400-16) ~19.5cm
•diagonal2 = 39cm
area = ½ × d¹ × d²
= 156cm²
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