If the perimeter of the trapezium is 42cm, a =10 b= 20 c = 6 d=?If the perimeter of the trapezium is 42cm, a =10 b= 20 c = 6 d=?
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Given perimeter of trapezium is equal to 42 cm
Sides, a=10 cm, b=20 cm, c= 6 cm
Formula perimeter of trapezium = sum of four sides
Therefore, 42= 10+20+6+d
42= 36+d
42-36=36-36+d (subtract 36 from both the sides)
42-36=d
6=d
Therefore value of D= 6 cm
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