If the perimeter of triangle is given by 3x-y+6 and two of it sides are given by 4x-9 and 12y-x+8 find its 3rd side. 0
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Answer:
Perimeter is nothing but sum all sides of triangle
therefore
3x-y+6 = 4x-9 + 12y-x+8 + z where z = 3rd side of triangle
3x-y+6 = 3x + 12y -1 +z
z = -y - 12y + 3x - 3x + 6+1
z = -13y +7
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