Question

if the perimeter of two squares are 24 cm and 52 cm. what will be the area of the square whose perimeter is equal to the sum of the perimeters of these two squares ?​

Answer 1

Answer:

If the perimeter of the two squares is 24 cm and 52 cm, then the area of the square whose perimeter is equal to the sum of the perimeters of these two squares is 361 sq. cm.

Step-by-step explanation:

Method 1:

The sum of the perimeters of these two squares  = 24 + 52 = 76 cm

So, 4 (side) = 76

side = 76/4

side = 19 cm

So, area of this square = side  × side

= 19  × 19

= 361 sq. cm

So, the area of the square whose perimeter is equal to the sum of the perimeters of these two squares is 361 sq. cm.

Method 2:

If the perimeter of two squares are 24 cm and 52 cm.

If perimeter of first square = 24 cm

4 (side) = 24

side = 24/4

side = 6 cm

If perimeter of second square = 52 cm

4 (side) = 52

side = 52/4

side = 13 cm

So, length of new square = 6 + 13 = 19 cm.

So, area of this square = side  × side

= 19  × 19

= 361 sq. cm

So, the area of the square whose perimeter is equal to the sum of the perimeters of these two squares is 361 sq. cm.