if the perimeter pf a rectangle is 138m and there
differencebetween the lenght & breadth is 7 m,
what is the area of the rectangle
Answers
Answered by
2
Answer:
A = 434 m²
Step-by-step explanation:
For you By islam_luv
Answered by
1
Given==> Perimeter of rectangle = 138 m
Let length = x and breadth = y
So, x-y = 7m ≈> 1
So now adjust equation 1.
x= 7+y
Perimeter of rectangle= 2 (l+b)
138 = 2 (x+y) ,(put value of x here)
138 = 2 (7+y+y)
69 = 7+2y
2y = 62
y = 31 m
So now put value of y in adjustment of equation 1.
x = 7 + y
x = 7 +31
x = 38 m
So, now we have to find the area!
Area of rectangle = l×b
Therefore, area of rectangle = 31 × 38
= 1178 m²
Answer :- 1178 m²
hope my explanation helped you friend!
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