Math, asked by venkydadi060, 5 hours ago

if the perimeter pf a rectangle is 138m and there
differencebetween the lenght & breadth is 7 m,
what is the area of the rectangle

Answers

Answered by Islamxluv
2

Answer:

A = 434 m²

Step-by-step explanation:

For you By islam_luv

Answered by friends1664
1

Given==> Perimeter of rectangle = 138 m

Let length = x and breadth = y

So, x-y = 7m ≈> 1

So now adjust equation 1.

x= 7+y

Perimeter of rectangle= 2 (l+b)

138 = 2 (x+y) ,(put value of x here)

138 = 2 (7+y+y)

69 = 7+2y

2y = 62

y = 31 m

So now put value of y in adjustment of equation 1.

x = 7 + y

x = 7 +31

x = 38 m

So, now we have to find the area!

Area of rectangle = l×b

Therefore, area of rectangle = 31 × 38

= 1178 m²

Answer :- 1178 m²

hope my explanation helped you friend!

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