If the perimter of a isocles traingle is 12m and one of eqal sides is 5m then find its area
Answers
Perimeter of an isosceles triangle ABC = 12m
let AB and AC be equal sides and BC be base
Equal sides length=5cm
Other side=12-10=2
Then, Side AB = 5m
Side AC = 5m
Side BC = 2m
A perpendicular line AD divides triangle ABC into two equal parts, and as well divides its base (that is, BC) into two equal parts, that is, BD and BC.
BD = BC/2 = 2/2 = 1m.
Using the Pythagoras theorem
(AB)^2 = (AD)^2 + (BD)^2
(AD)^2 = (AB)^2 - (BD)^2
AD = sqrt((AB)^2 - (BD)^2)
AD = sqrt((5)^2 - (1)^2))
AD = sqrt(25 - 1)
AD = sqrt(24)
AD = 2√6
The height of the triangle = 2√6m
While, its area = 1/2*b*h
= (1/2)*1*2√6
= √6 sq. meter.
Area of triangle is √6 sq.m
Answer:
Step-by-step explanation:
PERIMETER= SUM OF ALL SIDES
12=10 + x
x=2
THE OTHER SIDE Is 2 C M
AREA= ½( S(s-a)(s-b)(s-c))
S=5+5+2÷2=6
Area=½(6(6-5)(6-5)(6-2))
Area=½(6×1×1×4)
Area=½(24)
Area=2underroot6