if the period of the function f(x)= sin^4x -cos^4x is mπ/n where m and n are co prime then find the value of (mn)^2
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SOLUTION
GIVEN
The period of the function
is mπ/n where m and n are co prime
TO DETERMINE
The value of (mn)²
EVALUATION
Here the given function is
We simplify it as below
So period of f(x) = π
Now it is given that the period of f(x) is mπ/n
Thus we have m = 1 , n = 1
Therefore (mn)²
= (1 × 1)²
= 1
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