Question

If the permissible values of Azimuthal quantum
number (I)in an atom are: 0,1,2,.....n, all other
rules being unchanged, the magnetic moment of
Fe(Z=26) atom would be
(A) V24BM
(B) (35BM
(C) V15BM
(D) 18BM​

Answer 1

Answer:

root (24) B.M

Explanation:

magnetic moment (mu) = root( n(n+2) )...where n denotes the number of unpaired electrons.

the electronic configuration of Fe = [Ar]4s^2 3d^6....so it has 4 unpaired electrons.

therefore mu = root( 4(4+2) ) = root( 4(6) ) = root (24) B.M