If the permiter of a protractor is 36cm find its area
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Given perimeter of protractor(semicircle) = 36cm
⇒ (πd)/2 +d = 36
⇒ [(22/7)+d]/2 + d = 36
⇒ (22d)/14 +d = 36
⇒ (22d + 14d)/14 = 36
⇒ 36d = 36×14
⇒ d = (36×14)/36
∴ d = 14cm
Diameter= 14cm
Radius = 7cm
Area of semicircle = 1/2 πr²
= (1/2)×(22/7)×(49) cm²
= 77cm²
⇒ (πd)/2 +d = 36
⇒ [(22/7)+d]/2 + d = 36
⇒ (22d)/14 +d = 36
⇒ (22d + 14d)/14 = 36
⇒ 36d = 36×14
⇒ d = (36×14)/36
∴ d = 14cm
Diameter= 14cm
Radius = 7cm
Area of semicircle = 1/2 πr²
= (1/2)×(22/7)×(49) cm²
= 77cm²
Answered by
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I THINK THE ANSWER IS 77 BECAUSE THE RADIUS IS 7 SO ON THE BASIC FORMULA( PI R SQUARE DIVIDED BY TWO)
ANSWER IS 77
IF MY ANSWER IS CORECT MARK IT AS BRAINLY ANSWER
ANSWER IS 77
IF MY ANSWER IS CORECT MARK IT AS BRAINLY ANSWER
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